What is the coefficient for H2O when the following equation is balanced: Mg3N2 + H2O → Mg(OH)2 + NH3?
When the following reaction is balanced, what is the coefficient for O2?
H2 + O2 → H2O
Would the answer be 2?
Mg3N2+6 H20 >>> 3Mg(OH)2 +2 NH3
Surely you can balance the second equation.
To balance a chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Let's balance the given equation: Mg3N2 + H2O → Mg(OH)2 + NH3.
To balance the hydrogen (H) atoms, we need to put a coefficient of 3 in front of the water (H2O). This gives us:
Mg3N2 + 3H2O → Mg(OH)2 + NH3.
Now let's balance the nitrogen (N) atoms. There are already 2 nitrogen atoms on the left side, and only 1 on the right side. To balance it, we need to put a coefficient of 2 in front of the ammonia (NH3). This gives us:
Mg3N2 + 3H2O → Mg(OH)2 + 2NH3.
Finally, let's balance the magnesium (Mg) and hydroxide (OH) atoms. We can see that there are 3 magnesium atoms on the left side, and only 1 on the right side. To balance it, we put a coefficient of 3 in front of the magnesium hydroxide (Mg(OH)2). This gives us:
3Mg3N2 + 3H2O → 3Mg(OH)2 + 2NH3.
Therefore, the balanced equation is 3Mg3N2 + 3H2O → 3Mg(OH)2 + 2NH3.
Now let's move on to the second question: H2 + O2 → H2O.
Here, the coefficient for O2 is already provided as 2. So, the coefficient for O2 is indeed 2.