a ball with a mass 0.9 kg and velocity 10 m/s hits another ball with the same mass. the first ball stops moving and the second ball then moves forward and hits a third ball with mass of 0.3 kg. if the system is closed what is the velocity of the third bal?
First, we can calculate the momentum of the first ball before the collision:
p = m1 * v1
p = 0.9 kg * 10 m/s
p = 9 kg m/s
Since the first ball stops moving after the collision, the momentum of the system is transferred to the second ball. Therefore, the momentum of the second ball after the collision is also 9 kg m/s.
Next, we can calculate the velocity of the second ball after the collision using the momentum formula:
p = m2 * v2
9 kg m/s = 0.9 kg * v2
v2 = 10 m/s
Now, the second ball with a velocity of 10 m/s hits the third ball with a mass of 0.3 kg. We can calculate the velocity of the third ball using the momentum formula again:
p = m3 * v3
9 kg m/s = 0.3 kg * v3
v3 = 30 m/s
Therefore, the velocity of the third ball is 30 m/s.