What is the area for the horizontal cross section through the center of a sphere with a radius of 4 in.?(1 point)
The area of the horizontal cross section through the center of a sphere is equal to the area of a circle with a radius equal to the diameter of the sphere. In this case, the diameter of the sphere is twice the radius, so the diameter is 8 inches.
Therefore, the area of the horizontal cross section through the center of the sphere is:
A = π * (8/2)^2
A = π * 4^2
A = π * 16
A = 16π
So, the area of the horizontal cross section through the center of a sphere with a radius of 4 inches is 16π square inches.