Solve: log2 (3x + 1) = 4
To solve the equation log2(3x + 1) = 4, we first need to rewrite it in exponential form.
In exponential form, the equation log2(3x + 1) = 4 becomes:
2^4 = 3x + 1
Simplify the left side of the equation:
16 = 3x + 1
Subtract 1 from both sides:
15 = 3x
Divide by 3:
x = 5
Therefore, the solution to the equation log2(3x + 1) = 4 is x = 5.