Solve: log2 (3x + 1) = 4

To solve the equation log2(3x + 1) = 4, we first need to rewrite it in exponential form.

In exponential form, the equation log2(3x + 1) = 4 becomes:

2^4 = 3x + 1

Simplify the left side of the equation:

16 = 3x + 1

Subtract 1 from both sides:

15 = 3x

Divide by 3:

x = 5

Therefore, the solution to the equation log2(3x + 1) = 4 is x = 5.