Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below:

The art shows two figures. The figure on the left shows two rays BA and BC with a common endpoint B. An arc drawn from B cuts the ray BA at H and the ray BC at I. The figure on the right shows two rays ED and EF with a common endpoint E. An arc drawn from E cuts the ray ED at J and the ray EF at K. Another arc drawn from K cuts the ray ED at J.

Which statement best explains why Ben uses the width BI to create the arc JK from point E?

∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ.
BI = JK when ∠DEF ≅ ∠ABC.
BI = EJ when ∠DEF ≅ ∠ABC.
∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

The statement "∠DEF ≅ ∠ABC when BH = EK, BI = JK, and HI = EJ" best explains why Ben uses the width BI to create the arc JK from point E. This is because the equality in measures and lengths of various parts in both figures ensures that ∠DEF is congruent to ∠ABC.