Use the image to answer the question.
An illustration shows an arrow pointing both right and left. It is formed by triangles on the right and left connected by a rectangle in the middle. The length of the rectangle measures 16 inches, and the width measures 3 inches. The perpendicular height of the triangle on the right is shown by a horizontal dotted line from the right vertex to the base. The perpendicular height measures 8 inches. The length of the base of the triangle measures 10 inches.
A school hallway has a bidirectional arrow showing which way traffic can move. The dimensions of the sign are shown. What is the arrow’s area?
(1 point)
Responses
48 in.2
48 in. squared
128 in.2
128 in. squared
80 in.2
To find the area of the arrow, we need to find the combined areas of the two triangles on the right and left, and the rectangle in the middle.
Area of triangle on the right = 0.5 * base * height
Area of triangle on the right = 0.5 * 10 in * 8 in = 40 in^2
Area of triangle on the left = Area of triangle on the right (since they are congruent) = 40 in^2
Area of rectangle = length * width
Area of rectangle = 16 in * 3 in = 48 in^2
Total area = 40 in^2 + 40 in^2 + 48 in^2 = 128 in^2
Therefore, the arrow's area is 128 in^2.