Two machines at a factory are filling cans of soup. One machine has filled 92 cans of soup. It fills cans at a rate of 16 cans per minute. The second machine has filled 104 cans of soup. It fills cans at a rate of 13 cans per minute. Write and solve an equation to show when the two machines will have filled the same number of cans of soup.(1 point)
Responses
104+16x=92+13x ; x=4
104 plus 16 x equals 92 plus 13 x ; x equals 4
92+16x=104+13x ; x=4
92 plus 16 x equals 104 plus 13 x ; x equals 4
92+16x=104+13x ; x=6
92 plus 16 x equals 104 plus 13 x ; x equals 6
92−16x=104−13x ; x=−4
92 + 16x = 104 + 13x ; x = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.