A sample of methane gas at a pressure of 0.567 atm and a temperature of 267 °C, occupies a volume of 418 mL. If the gas is cooled at constant pressure until its volume is 293 mL, the temperature of the gas sample will be
°C.
To solve this problem, we can use the combined gas law equation:
(P1V1)/T1 = (P2V2)/T2
Where:
P1 = 0.567 atm
V1 = 418 mL
T1 = 267 °C + 273 = 540 K
P2 = 0.567 atm (constant pressure)
V2 = 293 mL
T2 = ? °C
Plugging in the values, we get:
(0.567 * 418)/540 = (0.567 * 293)/T2
241.506/540 = 165.831/T2
T2 = (165.831 * 540)/241.506
T2 = 371 K
Therefore, the temperature of the gas sample will be 371 K, which is equivalent to 98 °C.