Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it feels at a rate of 16 cans per minute the second machine has failed 104 cans of soup it fails cans at a rate of 13 cans per minute.Right and solve an equation to show when the two machines will have filled the same number of cans of soup
keyword: EQUATION.
Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.
Machine 1: 16 cans/minute
Machine 2: 13 cans/minute
The equation can be set up as:
92 + 16x = 104 + 13x
Solve for x:
16x - 13x = 104 - 92
3x = 12
x = 4
Therefore, it will take 4 minutes for the two machines to have filled the same number of cans of soup.
write a damn equation!!!!!!!!!!!!!!!!!!!!!
Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.
Machine 1:
Cans filled = 92 + 16x
Machine 2:
Cans filled = 104 + 13x
To find when the two machines will have filled the same number of cans of soup, set the two equations equal to each other:
92 + 16x = 104 + 13x
Solving this equation will give you the answer for when the two machines will have filled the same number of cans of soup.