Is (−2, 6) a solution to the system of these linear equations: x+2y=10 and 3x+y=0 ? Why?(1 point)

Responses

No, because the graphs intersect at (−2, 6).
No, because the graphs intersect at left parenthesis negative 2 comma 6 right parenthesis .

Yes, because the graphs don’t intersect at (−2, 6).
Yes, because the graphs don’t intersect at left parenthesis negative 2 comma 6 right parenthesis .

Yes, because the graphs intersect at (−2, 6).
Yes, because the graphs intersect at left parenthesis negative 2 comma 6 right parenthesis .

No, because the graphs don’t intersect at (−2, 6).

No, because the point (−2, 6) does not satisfy either of the equations in the system. When you substitute x = -2 and y = 6 into the first equation x + 2y = 10 you get -2 + 2(6) = 10 which simplifies to 10 = 10. However, when you substitute x = -2 and y = 6 into the second equation 3x + y = 0 you get 3(-2) + 6 = 0 which simplifies to 0 = 0. Therefore, the point (−2, 6) is not a solution to the system of linear equations.

Answer one of the choices please.

No, because the graphs intersect at (−2, 6).