Rewrite the function f(x)= 0.04^x/2 in the form f(x) = a(1+ r)^x. What are the values of a and r.
a =
r =
When x increases by 1, the function increases or decrease by 40%, 20%, 80%
First, we need to rewrite the original function in the desired form:
f(x) = 0.04^(x/2) = (0.04^(1/2))^x = (0.2)^x
Now we see that a = 1 and r = 0.2.
When x increases by 1, the function becomes f(x+1) = (0.2)^(x+1) = 0.2*(0.2)^x = 0.2*f(x).
This means the function decreases by 80% when x increases by 1.