following.
A ball is thrown from an initial height of 3 meters with an initial upward velocity of 11 m/s. The ball's height h (in meters) after t seconds is given by the
H=3+11t-5t^2
Given the height function H = 3 + 11t - 5t^2, we can use this equation to determine the height of the ball at any given time t.
To find the height of the ball after 2 seconds, we substitute t = 2 into the equation:
H(2) = 3 + 11(2) - 5(2)^2
H(2) = 3 + 22 - 5(4)
H(2) = 3 + 22 - 20
H(2) = 25 meters
Therefore, the height of the ball after 2 seconds is 25 meters.