Find the slope of a line parallel to the line whose equation is 10, x, plus, 12, y, equals, minus, 12010x+12y=−120. Fully simplify your answer.
To find the slope of the line given by the equation 10x + 12y = -120, we first need to rewrite the equation in slope-intercept form (y = mx + b), where m is the slope of the line.
10x + 12y = -120
12y = -10x - 120
y = (-10/12)x - 120/12
y = (-5/6)x - 10
Therefore, the slope of the line is -5/6.
Since the slope of a line parallel to a given line is the same, the slope of a line parallel to the line 10x + 12y = -120 is also -5/6.