Find the slope of a line perpendicular to the line whose equation is 3, x, minus, 5, y, equals, 453x−5y=45. Fully simplify your answer.
To find the slope of the line represented by the equation 3x - 5y = 45, we first need to rewrite it in slope-intercept form, which is y = mx + b, where m is the slope of the line.
3x - 5y = 45
-5y = -3x + 45
y = (3/5)x - 9
The slope of the line is 3/5.
The slope of a line perpendicular to this line would be the negative reciprocal of 3/5. Therefore, the slope of a line perpendicular to the line represented by the equation 3x - 5y = 45 is -5/3.