32.0g of oxygen and 44.0g of carbon dioxide each occupies 22.4dm3 at s.t.p
To calculate the volume occupied by 32.0g of oxygen at STP, we first need to find the number of moles of oxygen using its molar mass.
Molar mass of oxygen (O2) = 32.0 g/mol
Number of moles of oxygen = 32.0g / 32.0g/mol = 1 mol
Since 1 mole of any gas occupies 22.4 dm³ at STP, 32.0g of oxygen will also occupy 22.4 dm³ at STP.
Similarly, for 44.0g of carbon dioxide (CO2):
Molar mass of carbon dioxide (CO2) = 44.0 g/mol
Number of moles of carbon dioxide = 44.0g / 44.0g/mol = 1 mol
Therefore, 44.0g of carbon dioxide will also occupy 22.4 dm³ at STP.