angle ACB and angle BCD are supplementary angles. the anyles have rhe following measures: ACB = (x + 28)° and BCD = (x + 48)° what is m-angle/BCD?
If angle ACB and angle BCD are supplementary, then their measures add up to 180 degrees.
So, we have the equation: ACB + BCD = 180
Substituting the given measures: (x + 28) + (x + 48) = 180
Combining like terms: 2x + 76 = 180
Subtracting 76 from both sides: 2x = 104
Dividing both sides by 2: x = 52
So, the measure of angle BCD is (x + 48) = 52 + 48 = 100 degrees.
Therefore, m-angle BCD is 100 degrees.