What is the number of moles in 423 g Ba(NO3)2
To find the number of moles in 423 g of Ba(NO3)2, we need to divide the given mass by the molar mass of the compound.
The molar mass of Ba(NO3)2 can be calculated by summing the molar masses of each individual element:
Ba: 1 x 137.33 g/mol = 137.33 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
O: 6 x 16.00 g/mol = 96.00 g/mol
Therefore, the molar mass of Ba(NO3)2 is:
137.33 g/mol + 28.02 g/mol + 96.00 g/mol = 261.35 g/mol
Now, we can calculate the number of moles by dividing the given mass by the molar mass:
423 g / 261.35 g/mol = 1.619 moles
So, there are approximately 1.619 moles in 423 g of Ba(NO3)2.