Two machines at a factor of filling cans of soup one machine has filled 92 cans of soup it feels at a rate of 16 cans per minute the second machine has failed 104 cans of soup it fails cans at a rate of 13 cans per minute.Right and solve an equation to show when the two machines will have filled the same number of cans of soup
Let "t" be the number of minutes it takes for the two machines to fill the same number of cans of soup.
The first machine fills cans at a rate of 16 cans per minute, so the number of cans it fills in "t" minutes is 16t.
The second machine fills cans at a rate of 13 cans per minute, so the number of cans it fills in "t" minutes is 13t.
We can set up the equation:
16t = 13t + (104 - 92) [The difference in the number of cans filled by the second machine is (104 - 92)]
Simplifying the equation, we get:
16t - 13t = 12
3t = 12
t = 4
Therefore, the two machines will have filled the same number of cans of soup after 4 minutes.