A 1.50x10cube is going up a road inclined at 10degrees. If the coefficient of friction is 0.7. Determine the force that will move the car up the inclined with a constant speed.
Given:
m=1.50x10cube
angle=10degrees
coefficient=0.7
Required:
F=?
PLEASE HELP..
the component of weight down the hill is mg*SinTheta.
The component of weight normal to the hill is mg*CosTheta
Friction down the hill is mg*mu*CosTheta
So the force down the hill is mg*mu*CosTheta+mgSinTheta
That force must be overcome to move the car up the hill.