A label on a bottle of HCL has the following information density 1.134gm cubic percentage purity 37%.determine the volume of the stock acid containing one mole of HCL ,explain how a molar solution can be prepared using the volume of stock acid obtained
To determine the volume of the stock acid containing one mole of HCl, we can use the formula:
Volume = Mass / Density
First, we need to calculate the mass of HCl in the stock acid. The percentage purity of 37% means that there are 37 grams of HCl in every 100 grams of stock acid. So, the mass of HCl can be calculated as:
Mass of HCl = (Percentage purity / 100) * Mass of stock acid
= (37 / 100) * 1.134 g/cm^3
= 0.41958 g/cm^3
Next, we can calculate the volume of the stock acid containing one mole of HCl using the molar mass of HCl. The molar mass of HCl is approximately 36.5 g/mol. Therefore:
Volume = Mass of HCl / Density
= (0.41958 g/cm^3) / (36.5 g/mol)
≈ 0.0115 cm^3/mol (rounded to four decimal places)
Now, to prepare a molar solution using the volume of stock acid obtained, we need to dilute the stock acid to a specific volume and concentration. Since we know the volume of stock acid needed to make one mole of HCl is 0.0115 cm^3, we can follow these steps:
1. Calculate the volume of stock acid required to make the desired concentration of molar solution. For example, if you want to prepare 1 liter (1000 cm^3) of a 1 molar (1M) solution, we can use the formula:
Volume of stock acid = (Volume of molar solution * Molar concentration) / (Volume of stock acid containing one mole of HCl)
= (1000 cm^3 * 1M) / (0.0115 cm^3/mol)
≈ 86,956.52 cm^3 (rounded to two decimal places)
So, you would need approximately 86,956.52 cm^3 or 86.96 liters of the stock acid to prepare 1 liter of a 1M HCl solution.
2. Take the calculated volume of stock acid and add it to a suitable container.
3. Add distilled water to the container to reach the final desired volume of the molar solution (e.g., 1 liter).
4. Mix the solution thoroughly until it is homogenous.
Now, you have prepared a molar solution of HCl using the volume of stock acid obtained.