How do i go about this problem?

a car starts from rest at a constant velocity and reaches a velocity of 25 m/s when it reaches 180 meters. What will be the velocity when it continues another 95 meters?


In the first sentence...

vf^2= vi^2 + 2ad solve for a.
Then, knowing the starting velocity (25m/s) for the second leg, and knowing a..

Same formula as above, solve for Vf

ok got it thanks

To solve this problem, you can use the equation for constant acceleration: v^2 = u^2 + 2as.

First, we need to find the initial velocity (u). The problem states that the car starts from rest (rest means the initial velocity is 0 m/s).

Next, we can substitute the given values into the equation: v^2 = 0^2 + 2a(180).

Since the car is moving with a constant velocity, the acceleration (a) is 0 m/s^2. So the equation becomes: v^2 = 0 + 2(0)(180).

Simplifying further: v^2 = 0.

Taking the square root on both sides, we find that the velocity (v) is also 0 m/s.

So, when the car continues another 95 meters, the velocity will still be 0 m/s because the car is moving at a constant velocity.

Therefore, the velocity when it continues another 95 meters will be 0 m/s.