workout the equation of a line that has gradient of 5 and passes through points -3,2
To find the equation of a line, we need both the gradient (m) and a point (x₁, y₁).
Given:
Gradient (m) = 5
Point: (-3, 2)
The equation of a line in slope-intercept form is y = mx + c, where m is the gradient and c is the y-intercept.
We can substitute the given point (-3, 2) into the equation to solve for the y-intercept (c).
2 = 5*(-3) + c
2 = -15 + c
c = 17
Now we have the y-intercept (c = 17), so we can write the equation as:
y = 5x + 17