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Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)Responses. 12x+180=15x+21012 x plus 180 equals 15 x plus 21012x−210=15x−18012 x minus 210 equals 15 x minus 18012x+210=15x+18012 x plus 210 equals 15 x plus 180210−12x=180−15x
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answered4 months ago