How can the polynomial 6d4 + 9d3 – 12d2 be factored?
(1 point)
Responses
3d2(2d2 + 3d – 4)
3 d 2 (2 d 2 + 3 d – 4)
3d2(3d2 + 6d – 9)
3 d 2 (3 d 2 + 6 d – 9)
3d(d3 + 3d2 – 4)
3 d ( d 3 + 3 d 2 – 4)
6d2(d2 + 3d3 – 6)
6 d 2 ( d 2 + 3 d 3 – 6)
The correct factoring of the polynomial 6d4 + 9d3 – 12d2 is:
3d2(2d2 + 3d – 4)