What are the coordinates of point �′ B'B
′
if � (5, −9) B\ \left(5,\ -9\right)B (5, −9) is rotated 270°270\degree270° clockwise around the origin. Click for Help Video.
Your answer must be listed as a coordinate so use parenthesis.
To rotate a point 270° clockwise around the origin, we can use the following formulas:
x' = x * cos(270°) - y * sin(270°)
y' = x * sin(270°) + y * cos(270°)
Substituting the given coordinates (x = 5, y = -9), we get:
x' = 5 * cos(270°) - (-9) * sin(270°)
= 5 * 0 - (-9) * (-1)
= 0 + 9
= 9
y' = 5 * sin(270°) + (-9) * cos(270°)
= 5 * (-1) + (-9) * 0
= -5 + 0
= -5
Therefore, the coordinates of point B'B are (9, -5).