From a base elevation of 8200 ft. a mountain peak in colorado rises to a summit elevation of 14588 ft. over a horizonal distance of 15842 ft. find the grade of the peak.
The grade of the peak.
The grade of the peak is %.
Round to the nearest tenth as needed.
Someone help please!!
Thank you.
X+3y= 6 find the slope m=3 I'm I correct
To calculate the slope, calculate the
rise (vertical) = 14588 - 8200 ft
run (horizontal) = 15842 ft
The slope is rise/run, convert to 100%.
Determine whether 7.5 is a soultion for the inequality.X>5. i chose yes I'm I correct
You're correct, but draw them on the number line to make sure you understand the answer.
-∞----+0------+5---------+7.5----------+∞
Numbers on the right are greater than the numbers on the left. So if 7.5 is situated on the right of 5, then it is greater than 5.
Solve, 5X>45. The correct solution is
X[X>9 I'm I correct or close to it
Yes, it's correct, I think you got the hang of it.
How about
4-3x>16 ?
To find the grade of the peak, you can use the formula:
Grade = (Change in elevation / Horizontal distance) × 100
In this case, the change in elevation is the difference between the summit elevation and the base elevation, which is 14588 ft - 8200 ft = 6388 ft.
The horizontal distance is given as 15842 ft.
So, plugging the values into the formula:
Grade = (6388 ft / 15842 ft) × 100
Now, let's calculate the answer:
Grade = (0.403 × 100) = 40.3 %
Therefore, the grade of the peak is approximately 40.3%.