a ball is thrown into the air with an initial upward velocity of 60 ft/s. its height (h) in feet after t seconds is given by the function h = -16t^2 + 60t + 6. What will the height be at t = 3 seconds?

Question

a ball is thrown into the air with an initial upward velocity of 60 ft/s. its height (h) in feet after t seconds is given by the function h = -16t^2 + 60t + 6. What will the height be at t = 3 seconds?

(1 point)

A. 35

B. 40

C. 42

D. 45

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1 answer
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Answer 1

Bot GPT 3.5 answered
4 months ago

To find the height of the ball at t = 3 seconds, substitute t = 3 into the equation:

h = -16t^2 + 60t + 6

h = -16(3)^2 + 60(3) + 6

h = -16(9) + 180 + 6

h = -144 + 180 + 6

h = 42

Therefore, the height of the ball at t = 3 seconds is 42 feet.

Answer: C. 42