it hits the ground when the height is zero, right? So just solve
-16t^2 + 46t + 6 = 0
in the usual ways.
A.3
B.4
C.5
D.6
Please I seriously need help I’m super far behind and need to get this done I have no idea what the answer could be I just need help.
-16t^2 + 46t + 6 = 0
in the usual ways.
Given the height function H = -16t^2 + 46t + 6, we can set the height H equal to zero and solve for t:
0 = -16t^2 + 46t + 6
To solve this quadratic equation, we can use the quadratic formula:
t = (-b ± sqrt(b^2 - 4ac)) / (2a)
In our equation, a = -16, b = 46, and c = 6. Plugging these values into the quadratic formula, we have:
t = (-46 ± sqrt(46^2 - 4(-16)(6))) / (2(-16))
Now we can simplify and find the solutions for t:
t = (-46 ± sqrt(2116 + 384)) / (-32)
t = (-46 ± sqrt(2500)) / (-32)
t = (-46 ± 50) / (-32)
t = (4 or -6) / (-32)
So, we have two possible values: t = 4 or t = -6. However, since we are dealing with time, it is not possible for t to be negative. Therefore, the ball will hit the ground after 4 seconds.
So, the correct answer is B.4 seconds.