The sides of a triangular path measure 7 m, 9 m, and 11 m. Find the perimeter of a similar triangle in which the shortest side has a length of 21 meters.(1 point)
Responses
33 m
33 m
27 m
27 m
21 m
21 m
81 m
To find the perimeter of a similar triangle, we can use the concept of ratios.
If the shortest side of the original triangle measures 7 m and the shortest side of the similar triangle measures 21 m, the ratio of their lengths would be 21/7 = 3.
Therefore, we can multiply all the sides of the original triangle by 3 to find the lengths of the corresponding sides in the similar triangle.
The new lengths would be:
Shortest side: 7 m * 3 = 21 m
Middle side: 9 m * 3 = 27 m
Longest side: 11 m * 3 = 33 m
So the perimeter of the similar triangle is 21 m + 27 m + 33 m = 81 m.
Therefore, the correct answer is 81 m.