△CDE∼△PQR . m∠C=13° , m∠D=65° . What are the measures of angles P , Q , and R ?(2 points)
Since ∆CDE ∼ ∆PQR, the corresponding angles are equal.
Therefore, we know that:
m∠C = m∠P
m∠D = m∠Q
Given that m∠C = 13° and m∠D = 65°,
we can conclude that:
m∠P = 13°
m∠Q = 65°
To find m∠R, we know that the sum of the angles in a triangle is 180°.
m∠C + m∠D + m∠R = 180°
13° + 65° + m∠R = 180°
78° + m∠R = 180°
m∠R = 180° - 78°
m∠R = 102°
Therefore, the measures of angles P, Q, and R are:
m∠P = 13°
m∠Q = 65°
m∠R = 102°