Find the slope of a line perpendicular to the line whose equation is 10, x, minus, 12, y, equals, minus, 2410x−12y=−24.
To find the slope of a line perpendicular to the given line, we need to first find the slope of the given line.
The equation of the given line is given as 10x - 12y = -24.
We can rearrange the equation in slope-intercept form, y = mx + b, where m is the slope:
-12y = -10x - 24
Dividing both sides by -12:
y = (10/12)x + 2
Simplifying:
y = (5/6)x + 2
So, the slope of the given line is 5/6.
The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line.
Therefore, the slope of a line perpendicular to the given line is -6/5.