Triangle ABC has vertices point A (2,1) point B (4,3) and point C (-2,5). Find the coordinates of A' B' and C' after a dilation with a scale factor of 7 and a center point of dilation at the origin (0,0)
A' =
B' =
C' =
To find the coordinates of A', B', and C' after a dilation with a scale factor of 7 and a center point of dilation at the origin (0,0), we can use the formula for dilation:
(x', y') = (k * x, k * y)
Where (x, y) are the original coordinates, (x', y') are the coordinates after dilation, and k is the scale factor.
For point A (2, 1):
x' = 7 * 2 = 14
y' = 7 * 1 = 7
So, A' = (14, 7)
For point B (4, 3):
x' = 7 * 4 = 28
y' = 7 * 3 = 21
So, B' = (28, 21)
For point C (-2, 5):
x' = 7 * -2 = -14
y' = 7 * 5 = 35
So, C' = (-14, 35)
Therefore, the coordinates of A' are (14, 7), the coordinates of B' are (28, 21), and the coordinates of C' are (-14, 35).