# I am supposed to preform the indicated divisons:

8x^3-6x^2+2x divided by 4x+1

I am so lost right now, not understanding this at all!

## Look at this example:

http://www.sosmath.com/algebra/factor/fac01/fac01.html

## Thanks, would this be correct though?

2x^2+1x 1x/4x+1

## To perform the division (8x^3 - 6x^2 + 2x) ÷ (4x + 1), you can use the long division method. Here's a step-by-step explanation:

Step 1: Start by dividing the highest degree term of the dividend (8x^3) by the highest degree term of the divisor (4x).

8x^3 ÷ 4x = 2x^2

Write this as the first term of the quotient.

Step 2: Multiply the entire divisor (4x + 1) by the first term of the quotient (2x^2) and subtract the result from the dividend.

(2x^2)(4x + 1) = 8x^3 + 2x^2

So, subtracting this from the dividend:

(8x^3 - 6x^2 + 2x) - (8x^3 + 2x^2) = -8x^2 + 2x

Step 3: Bring down the next term from the dividend (-8x^2) and divide it by the highest degree term of the divisor (4x).

-8x^2 ÷ 4x = -2x

Write this as the second term of the quotient.

Step 4: Multiply the entire divisor (4x + 1) by the second term of the quotient (-2x) and subtract the result from the previous result.

(-2x)(4x + 1) = -8x^2 - 2x

So, subtracting this from the previous result:

(-8x^2 + 2x) - (-8x^2 - 2x) = 4x

Step 5: Bring down the next term from the dividend (4x) and divide it by the highest degree term of the divisor (4x).

4x ÷ 4x = 1

Write this as the third term of the quotient.

Step 6: Multiply the entire divisor (4x + 1) by the third term of the quotient (1) and subtract the result from the previous result.

(1)(4x + 1) = 4x + 1

So, subtracting this from the previous result:

(4x) - (4x + 1) = - 1

Step 7: There are no more terms to bring down, so the division is complete.

Putting it all together, the quotient is 2x^2 - 2x + 1 with a remainder of -1.