Use the image to answer the question.%0D%0A%0D%0A%0D%0A%0D%0AWhat can be the value of x%0D%0A%0D%0A so that the ordered pair (x, 13) is located in Quadrant II?%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A13%0D%0A13%0D%0A%0D%0A−14%0D%0Anegative 14%0D%0A%0D%0A0%0D%0A0%0D%0A%0D%0A9%0D%0A9%0D%0ASkip to navigation%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0A%0D%0AHighlight
Based on the image provided, the value of x that would place the ordered pair (x, 13) in Quadrant II is -14. Therefore, the correct answer is -14 or negative 14.
