Use the image to answer the question.
An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.
Translate figure PQRS 6 units down and 2 units to the right. What are the coordinates of P′ ?
(1 point)
Responses
(10, 4)
left parenthesis 10 comma 4 right parenthesis
(2, 12)
left parenthesis 2 comma 12 right parenthesis
(2, 0)
left parenthesis 2 comma 0 right parenthesis
(6, 0)
left parenthesis 6 comma 0 right parenthesis
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To translate figure PQRS 6 units down and 2 units to the right, we subtract 6 from the y-coordinate of each vertex and add 2 to the x-coordinate of each vertex.
So the new coordinates of P' would be (4+2, 6-6) which simplifies to (6, 0).
Therefore, the correct answer is (6, 0).