D varies p and d= 0.2 when p=10 find
A) D when p =18
B) P when d=1.1
To find the value of D when P = 18, we can use the ratio of the change in D to the change in P when P increases from 10 to 18.
The ratio of the change in D to the change in P is constant, so we can set up the following proportion:
(Change in D) / (Change in P) = (D2 - D1) / (P2 - P1)
Let's plug in the given values:
D1 = 0.2 (when P = 10)
P1 = 10
P2 = 18
From this information, we can calculate the change in D:
Change in D = (D2 - D1) = (D2 - 0.2)
Plugging this into the proportion:
(Change in D) / (Change in P) = (D2 - 0.2) / (18 - 10)
We want to find the value of D when P = 18, so we can rearrange the proportion and multiply both sides by the change in P:
(Change in D) = (D2 - 0.2) * (Change in P)
Now we can substitute the known values:
(Change in D) = (D2 - 0.2) * (18 - 10)
(Change in D) = (D2 - 0.2) * 8
We also know that the change in D is equal to D2 - D1, so we can substitute it:
D2 - D1 = (D2 - 0.2) * 8
Expanding and simplifying:
D2 - 0.2 = 8D2 - 1.6
7.8 = 7D2
D2 = 7.8 / 7
D2 = 1.114
So, when P = 18, D ≈ 1.114. (Answer to part A)
Now let's find the value of P when D = 1.1. To do this, we can rearrange the original equation:
D = kp
Where k is the constant of variation. We can solve for P:
P = D / k
Since D = 1.1 and we don't have the exact value of k, we can't calculate the exact value of P. Without more information about the relationship between D and P, we can't determine P when D = 1.1. (Answer to part B)