There are 50 red beans and 50 white beans in a bag. The first bean selected is red. The red bean is returned to the bag.
What are the chances of the second bean selected being red?
Answer options with 5 options
A.
StartFraction 1 over 49 EndFraction
B.
StartFraction 1 over 50 EndFraction
C.
StartFraction 1 over 100 EndFraction
D.
StartFraction 49 over 100 EndFraction
E.
StartFraction 50 over 100 EndFraction
The chances of the second bean selected being red can be calculated using the formula:
Probability = Number of favorable outcomes / Number of possible outcomes
In this case, after returning the red bean to the bag, there are still 50 red beans remaining out of a total of 100 beans (50 red + 50 white). Therefore, the number of favorable outcomes is 50.
The number of possible outcomes is still 100, as there are still 100 beans in the bag.
So, the probability of the second bean selected being red is:
Probability = 50 red beans / 100 total beans = 1/2 = StartFraction 1 over 2 EndFraction
However, none of the given answer options match this probability exactly. The closest answer option is B. StartFraction 1 over 50 EndFraction, but it is not an exact match.