Our middle school is having a fall carnival. Admission into the carnival is $3 and each game inside the carnival costs $.25. Write an inequality that represents the possible number of games that can be played having $10. What is the maximum number of games that can be played?(1 point)
A.0.25x+3≤10
; 28 games
B.0.25x−3≤10
; 52 games
C.0.25x−3<10
; 52 games
D.0.25x+3<10
; 28 games
0.25x+3<10
; 28 games
To find the inequality that represents the possible number of games that can be played having $10, we need to take into account that the admission fee is $3 and each game costs $0.25.
Let x represent the number of games that can be played. The total cost of the games would be 0.25x. Since the total amount spent cannot exceed $10, we can write the inequality as:
0.25x + 3 ≤ 10
To find the maximum number of games that can be played, we need to solve this inequality for x. First, we subtract 3 from both sides of the inequality:
0.25x ≤ 7
Then, we divide both sides of the inequality by 0.25:
x ≤ 28
Therefore, the correct answer is A. 0.25x + 3 ≤ 10; 28 games.