Given point A (2, 4) on the triangle in Quadrant I, where is the new point if the triangle is rotated 90 degrees counterclockwise?
To rotate a point 90 degrees counterclockwise, we can use the following formulas:
new x-coordinate = -y-coordinate of the original point
new y-coordinate = x-coordinate of the original point
In this case, the original point A has coordinates (2, 4). Applying the formulas:
new x-coordinate = -4 = -4
new y-coordinate = 2
The new point, after rotating 90 degrees counterclockwise, is (-4, 2).