Two supplementary angles have the following measures: m∠ABC=135°%0D%0A%0D%0A∠%0D%0A%0D%0A%0D%0A%0D%0A=%0D%0A135%0D%0A°%0D%0A and m∠CBD=9x°%0D%0A%0D%0A∠%0D%0A%0D%0A%0D%0A%0D%0A=%0D%0A9%0D%0A%0D%0A°%0D%0A. What is the equation to solve for x%0D%0A%0D%0A?(1 point)%0D%0AResponses%0D%0A%0D%0A9x°+135°=180°%0D%0A9%0D%0A%0D%0A°%0D%0A+%0D%0A135%0D%0A°%0D%0A=%0D%0A180%0D%0A°%0D%0A9 x plus 135 equals 180%0D%0A%0D%0A9x°+135°=90°%0D%0A9%0D%0A%0D%0A°%0D%0A+%0D%0A135%0D%0A°%0D%0A=%0D%0A90%0D%0A°%0D%0A9 x plus 135 equals 90%0D%0A%0D%0A9x°=180°%0D%0A9%0D%0A%0D%0A°%0D%0A=%0D%0A180%0D%0A°%0D%0A9 x equals 180%0D%0A%0D%0A9x°−135°=180°
The correct equation to solve for x is:
9x° + 135° = 180°