How many digits are in the repeating cycle of 17/27
To find the repeating cycle of a fraction, we can perform long division.
When we divide 17 by 27, we get 0 with a remainder of 17. We then multiply the remainder (17) by 10 and divide it by 27. This gives us 6 with a remainder of 23. We repeat this process until we either get a remainder of 0 or until the remainder repeats itself.
The division process looks like this:
27 | 17 | ...
10
-----
7
6
-----
10
9
-----
10
9
------
...
After a few more iterations, we see that the remainder starts repeating at 10 and 9. Therefore, the repeating cycle of 17/27 is 10, 9, 10, 9, ...
Since the repeating cycle consists of 2 digits (10 and 9), there are 2 digits in the repeating cycle of 17/27.