An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.
If figure PQRS is translated 6 units up and 4 units to the left, what are the coordinates of point S′?
To translate a figure, we add or subtract the same amount from the x- and y-coordinates of each vertex of the figure. In this case, we want to translate the figure 6 units up and 4 units to the left.
The coordinates of point S are (2, 2).
To translate 4 units to the left, we subtract 4 from the x-coordinate: 2 - 4 = -2.
To translate 6 units up, we add 6 to the y-coordinate: 2 + 6 = 8.
Therefore, the coordinates of point S' are (-2, 8).