# (3-x)/-4=(x+6)/3

I have tried this one multiple times but i still can't get it.

## (3-x)/-4 = (x+6)/3

subtract the terms on the right over to the left (everything)

[(3-x)/-4]-[(x+6)/3]=0

find a common denominator
for 4 and 3 which is 12

[-3(3-x)/12]-[4(x+6)/12]=0

multiply over

(-9+3x)/12 - (4x+24)/12= 0

[(-9+3x)-(4x+24)]/12 = 0 don't forget the negative

(-3+3x-4x-24)/ 12 = 0

combine like terms on the numerator then solve for x

(-3+3x-4x-24)= 0

## Typo after multiply over: Correction

is it's -9 not negative -3

[(-9+3x)-(4x+24)]/12 = 0 don't forget the negative

(-9+3x-4x-24)/ 12 = 0

combine like terms on the numerator then solve for x

(-9+3x-4x-24)= 0

## To solve the equation (3-x)/-4=(x+6)/3, we can start by cross-multiplying. This means multiplying the numerator of the left side expression with the denominator of the right side expression, and vice versa.

First, cross-multiplying the left side:
(3-x) * 3 = -4 * (x+6)
Expanding both sides:
9 - 3x = -4x - 24

Next, we can simplify the equation by combining like terms. To do this, let's isolate the variables on one side of the equation and the constants on the other side.