Two questions:

1) NaCl+H2SO4+NH3=Cl2+?

2) KF+AgNO3+NH3=?

I've been agonising over these for the past few hours, but can't seem to make any headway. Please help.

1. Is the Cl2 given in the problem as one of the products or is that what you think? I don't believe Cl2 is produced.

NaCl + H2SO4 + NH3 ==> Na2SO4 + NH4Cl. You need to balance it. You may see this reaction better if we write it in two steps.
NaCl + H2SO4 ==> Na2SO4 + HCl (again, you balance). Then
HCl + NH3 ==> NH4Cl.
Add the two equations to get my original equation.

2. I'm cold on this. Obviously AgNO3 and NH3 will form the Ag(NH3)2^+ ion. AgF is soluble. The best I can come up with is to write the products as ions.
K^+ + (NH3)2^+ + NO3^-.
There is evidence that the AgX compounds form AgX2^- for AgCl, AgBr, and AgI but my copy of Inorganic Chemistry by Cotton and Wilkinson do not mention AgF falling into this category. The Merck Index says that AgF form the basic fluoride after long contact with water but no other information is given. I would be interested in knowing what you find.

1) Yes, Cl2 is definitely produced, we could see it, it stung our noses and we tested the gas. I know it's annoying, but please help!

2)Thank you!

Cl2 could not have been rpoduced, the gas you stung your noses on was the ammonium chloride, it sublimes so if you were to conduct this reaction but held a cold beaker above the gas you would notice that it crystallises over the top. Id love to know the answer to the 2nd question though!


To solve these chemical equations and determine the products, we need to understand the reactions and their respective rules.

1) NaCl + H2SO4 + NH3 = Cl2 + ?
This equation appears to involve the combination of sodium chloride (NaCl), sulfuric acid (H2SO4), and ammonia (NH3). The question mark denotes an unknown product.

However, this equation is not balanced, as the number of atoms on each side of the equation must be equal. To balance an equation, we need to ensure that the same number of each type of atom appears on both sides of the reaction arrow.

To balance this equation, we first need to identify the possible reactions. It seems unlikely that NaCl will directly react with H2SO4 or NH3. So let's consider two separate reactions.

Reaction 1: NaCl + H2SO4
This is a double displacement reaction where sodium chloride (NaCl) reacts with sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4) and hydrochloric acid (HCl). The balanced equation for this reaction is:
2 NaCl + H2SO4 → Na2SO4 + 2 HCl

Reaction 2: HCl + NH3
This is a neutralization reaction where hydrochloric acid (HCl) reacts with ammonia (NH3) to form ammonium chloride (NH4Cl). The balanced equation for this reaction is:
HCl + NH3 → NH4Cl

Now, we have identified the individual reactions and their products. Combining them, we can determine the final equation and the product:
2 NaCl + H2SO4 + 2 NH3 → Na2SO4 + 2 HCl + NH4Cl

2) KF + AgNO3 + NH3 = ?
Similarly, to solve this equation involving potassium fluoride (KF), silver nitrate (AgNO3), and ammonia (NH3), we follow a similar approach.

Let's consider two separate reactions:

Reaction 1: KF + AgNO3
This is a double displacement reaction where potassium fluoride (KF) reacts with silver nitrate (AgNO3) to form potassium nitrate (KNO3) and silver fluoride (AgF). The balanced equation for this reaction is:
KF + AgNO3 → KNO3 + AgF

Reaction 2: AgF + NH3
This is a complexation reaction where silver fluoride (AgF) reacts with ammonia (NH3) to form a complex called hexammine silver(I) fluoride [Ag(NH3)6]F. The balanced equation for this reaction is:
AgF + 6 NH3 → [Ag(NH3)6]F

Now, we can combine the two reactions to determine the final equation and the product:
KF + AgNO3 + 6 NH3 → KNO3 + [Ag(NH3)6]F

By following these steps and applying the principles of chemical reactions, we can determine the balanced equations and products for these chemical reactions.