Use the image to answer the question.

An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.

If figure PQRS is translated 6 units up and 4 units to the left, what are the coordinates of point S′ ?

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The coordinates of point S' after the translation would be (2-4, 2+6), which simplifies to (-2, 8). Therefore, the coordinates of point S' are (-2, 8).