The Ming family and the Harmon family are taking a road trip together but in separate cars. A few hours into the trip, both cars are traveling due east at a constant velocity. During that time, the Ming family’s car traveled 33 miles in 0.6 hours, and the Harmon family’s car traveled 90 miles in 1.5 hours. Which family’s car had the greater velocity?

Question

The Ming family and the Harmon family are taking a road trip together but in separate cars. A few hours into the trip, both cars are traveling due east at a constant velocity. During that time, the Ming family’s car traveled 33 miles in 0.6 hours, and the Harmon family’s car traveled 90 miles in 1.5 hours. Which family’s car had the greater velocity?

Answer 1

To find the velocity, we need to divide the distance traveled by the time taken for each car.

For the Ming family's car, the distance traveled is 33 miles and the time taken is 0.6 hours. Therefore, the velocity of the Ming family's car is 33 miles / 0.6 hours = 55 miles/hour.

For the Harmon family's car, the distance traveled is 90 miles and the time taken is 1.5 hours. Therefore, the velocity of the Harmon family's car is 90 miles / 1.5 hours = 60 miles/hour.

Therefore, the Harmon family's car had the greater velocity.