A 12kg box sits on top of a 38kg box.
a) Calculate the normal for acting on the 12k g box.
b) Calculate the normal force acting on the 38kg box due to the floor.
a) The normal force acting on the 12kg box is equal in magnitude and opposite in direction to the weight of the box. The weight is given by the formula:
Weight = mass * acceleration due to gravity
The acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the 12kg box is:
Weight = 12kg * 9.8 m/s^2 = 117.6 N
So, the normal force acting on the 12kg box is 117.6 N.
b) The normal force acting on the 38kg box is equal in magnitude and opposite in direction to the combined weight of the 12kg box and the 38kg box.
The weight of the 12kg box is 117.6 N, as calculated in part a). The weight of the 38kg box can be found similarly:
Weight = 38kg * 9.8 m/s^2 = 372.4 N
So, the combined weight of the two boxes is:
Weight = 117.6 N + 372.4 N = 490 N
Therefore, the normal force acting on the 38kg box due to the floor is 490 N.