Find the solution of the system of equations.
10, x, plus, 8, y, equals, 42
10x+8y=
42
minus, 8, x, minus, 8, y, equals, minus, 40
−8x−8y=
−40
The system of equations is:
10x + 8y = 42
-8x - 8y = -40
To find the solution, we can use the method of elimination. Adding the two equations together, we get:
(10x + 8y) + (-8x - 8y) = 42 + (-40)
Simplifying the left side and right side separately:
2x = 2
Dividing both sides of the equation by 2:
x = 1
Plugging this value of x back into one of the original equations, we can solve for y. Let's use the first equation:
10(1) + 8y = 42
Simplifying:
10 + 8y = 42
Subtracting 10 from both sides:
8y = 32
Dividing both sides by 8:
y = 4
Therefore, the solution to the system of equations is x = 1 and y = 4.