What is the sum of an arithmetic series where t1 = 1/2 , d = 3 and n=19
To find the sum of an arithmetic series, we can use the formula:
Sn = (n/2)(2t1 + (n-1)d)
Given that t1 = 1/2, d = 3, and n = 19, we can substitute these values into the formula:
Sn = (19/2)(2(1/2) + (19-1)(3))
= (19/2)(1 + 18(3))
= (19/2)(1 + 54)
= (19/2)(55)
= 19/2 * 55/1
= 1045/2
Therefore, the sum of the arithmetic series is 1045/2 or 522.5.