olve the system by either substitution or elimination.
3x−5y=212x+y=1 (1 point)
Responses
(2,−3)
(
2
,
−
3
)
open paren 2 comma negative 3 close paren
(2,3)
(
2
,
3
)
open paren 2 comma 3 close paren
(−2,−1)
(
−
2
,
−
1
)
open paren negative 2 comma negative 1 close paren
(−2,1)
To solve the system of equations by elimination, multiply the second equation by 5 to make the coefficients of y in both equations equal:
3x - 5y = 21
10x + 5y = 5
Adding the two equations eliminates the y variable:
13x = 26
x = 2
Substitute x = 2 into one of the original equations:
2(2) + y = 1
4 + y = 1
y = -3
Therefore, the solution to the system of equations is (2, -3).